# Just Average

Given a list of integers `nums`

and an integer `k`

, return `true`

if you can remove exactly one element from the list to make the average equal to exactly `k`

.

**Constraints**

`2 ≤ n ≤ 1,000`

where`n`

is length of`nums`

`nums[i], k ≤ 1,000,000`

https://binarysearch.com/problems/Just-Average

## Examples

### Example 1

**Input**

- nums =
`[1, 2, 3, 10]`

- k =
`2`

**Output**

- answer =
`True`

**Explanation**

We can take `10`

out to reach an average of `2`

since `(1 + 2 + 3) / 3 = 2`

### Example 2

**Input**

- nums =
`[1, 3]`

- k =
`2`

**Output**

- answer =
`False`

**Explanation**

If we remove `1`

, we get an average of `3`

and if we remove `3`

, we get an average of `1`

.

## Leave a comment